Can't quite figure this one out... any help?

bdonegan · #1 (**permalink**) 11-30-04, 06:10

I have 2 tables, one contains the details for all the documents stored on a server such as the documents name and which directory it is stored in, and the other contains the details for each document version (if there are any) these are paired up using the documents id, per example below

Documents
ID, Name, Dir
1, word.doc, /docs
2, excel.xls, /docs
3, webpage.html, /docs

Document Versions
ID
1
1
1
2
2
3

so, as you can see, in the versions table there are 3 versions of 'word.doc' 2 of 'excel.xls' and 1 of 'webpage.html'. i need to write a query that will return all the documents in the versions table who have a matching document in the documents table (that is not the major problem though) the main problem is that i only want to return it if the matching record in the documents table passes certain criteria, this being that it is from a certain site and has a particular type of file name. for example, i would like to return only the document versions whose parent records are '.doc' or '.xls' files, but not html. this would leave me with :

Versions
ID
1
1
1
2
2

leaving the last record out, as it's parent is a html file.

As a bonus, if you could tell me how to append the parents name to each record so i get a table like this :

Results
ID Name
1 'word.doc'
1 'word.doc'
1 'word.doc'
2 'excel.xls'
2 'excel.xls'

that would be great, thank you

Littlefoot · #2 (**permalink**) 11-30-04, 07:26

You didn't specify database engine you use; but, in Oracle it would be something like this:

Code:

SELECT d.id, d.name
FROM DOCUMENTS d, VERSIONS v
WHERE v.id = d.id
  AND SUBSTR(d.name, INSTR(d.name, '.', 1) + 1, LENGTH(d.name)) <> 'html';

WHERE clause will be different for another requirements, of course.

bdonegan · #3 (**permalink**) 11-30-04, 08:10

hmmm, not sure if that's quite it. and the database engine is SQL server

Pat Phelan · #4 (**permalink**) 11-30-04, 08:28

As I can't see a generic SQL solution, I'd recommend using:

Code:

SELECT d.id, d.name
   FROM documents AS d
   JOIN versions AS v
      ON (v.id = d.id)
   WHERE  d.name NOT LIKE '%.html'

-PatP

bdonegan · #5 (**permalink**) 11-30-04, 08:59

Got It! Thanks for your help though. This was the final solution for anyone who's interested

SELECT Docs.Name, DocVersions.TimeCreated, DocVersions.Content
FROM DocVersions INNER JOIN
Docs ON DocVersions.Id = Docs.Id
WHERE (Docs.LeafName LIKE '%.doc' OR
Docs.Name LIKE '%.xls' OR
Docs.Name LIKE '%.ppt' OR
Docs.Name LIKE '%.pdf' OR
Docs.Name LIKE '%.mpp' OR
Docs.Name LIKE ' % .txt ') AND (Docs.DirName LIKE 'sites/archive/%')

I think i confused u all with my talk of leaving out the html document. It wasn't so much i wanted to leave that out as include the others if you know what i mean

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