What is the dos command syntax to get the day of the current date.
For example today is Aug. 24, 2009, the day number should be 24.

I have a batch file wherein i need to know the day number.
Below is my sample command script:

IF %DATE% <= 7
(
echo Successful run: Email sent to users containing the final report file
)

ELSE

(
echo Error: Bugreport (Missing Report) email sent
)

Thanks.

try google
or consider switching to vbscript as an alternative to dos batch

This syntax returns the day number of the current date.

%Date:~0,2%

I used this in my IF condition, but when i tried running my batch file, i can't get the result.

@echo off

IF %Date:~0,2% > 8

(
echo PROCESS 3: successful >> test.log
echo. >> test.log
)

ELSE

(
echo PROCESS 4: failure>> test.log
echo. >> test.log
)

pause

:end

First off, I think, the arguments ~0,2 represent the positions and are dependant on the setting. Please check this out.

Secondly, > is a redirection symbol.
On XP, the batch command sysntax defines variables for string comparison. Help if at the comand prompt will give it to you.

Here is a sample batch file:
***********************************
@echo off
REM echo %%date:~0,2%
SET aa=%date:~0,2%
echo %aa%
If %aa% GTR 08 echo Greater than 8
If %aa% LEQ 07 echo Less than or equal to 7
echo.
If %aa% GTR 04 echo Greater than 4
If %aa% LEQ 03 echo Less than or equal to 3
***********************************

End