[prae]

Hello,

OS = HP11i
IDS= 7.10.UD3

SHMVIRTSIZE 131072
SHMADD 131072
SHMTOTAL 0


Block size = 2048 bytes



# onstat -g seg
INFORMIX-OnLine Version 7.10.UD3 -- On-Line -- Up 03:31:42 -- 694560 KbytesSegment Summary: (resident segments are not locked)id key addr size ovhd class blkused blkfree
...
...
1381386250 e68f5000 134217728 2652 V 1299 15085


If I take the size of V segment :
134217728 pages = 67108864 KB = 65536 MB

It is far from the value of SHMVIRTSIZE ....


And if I take
blkused + blkfree * 2048 = 16384 * 2048 = 32768 KB = 32 MB.


Once again, pretty different figures ....


So my question is :
Is there any trick, or ain't I doing the right sum or what ?


Cheers.

[prae]

Opps, sorry, I wrote :

If I take the size of V segment :
134217728 pages = 67108864 KB = 65536 MB

It is far from the value of SHMVIRTSIZE ....


In fact , the size in correct here, because in bytes ...

134217728 bytes = 131072 KB

which is well the value of SHMVIRTSIZE


The problem is with bock used and block free

[eherber]

(1299+15085)*8192 = 134217728

These are 8K-Blocks, they have nothing to do
with the page size.

BTW 7.10 is very very old and no longer supported
by Informix. Using such a version in a production
environment is unwarrantable.

[prae]

Thanks Eric

[doberls]

When you have,

size : 134217728

blkused : 1299
blkfree : 15085

blkused and blkfree are the number of 8Ko memory fragment and not 2 Ko pages.

So, ( 1299 + 15085 ) * 8 Ko = 132 Mo ... it's OK !