I am now doing one small project [Laboratory Information System] and facing this math's problem...ummm too long away from school and forgot all this...

ObjectA = 111000111 <----> First Object
ObjectB = 000110000
ObjectC = 100000000

ObjectA is the main value ,ObjectB and ObjectC is selectable.
When I compare those Object or few Objects , never to have 1's occur at the same position.Example :

0011
1100 give 1111 so no error and ASP script will be continue to next session.

BUT if

0011
1110 then will give error code because this 2 object at the 3rd position with 1.


So If ObjectA compare with Object B
ObjectA = 111000111 <----> First Object
ObjectB = 000110000
==============
111110111 <--- No error

But If
ObjectA = 111000111 <----> First Object
ObjectC = 100000000
===============
1011000111 < --- error

Can someone teach me how can I know that if those 2 object when compare, how the result value able to let me know rhere is error and which position of the 1's happen.

Thanks in advanced.

You need to do a logical AND:

111000111 AND 000110000 = 000000000

111000111 AND 100000000 = 100000000

So if the AND result = 0 you are OK

One way to then see which bits are set would be:

result = 111000111 AND 100000001

If result AND 100000000 > 0 then
/* bit 1 is set */
end if
If result AND 010000000 > 0 then
/* bit 2 is set */
end if
... etc.

Of course, you could do that in a loop something like:

FOR i = 1 TO 9 DO
isset(10-i) = result AND 2 ** i
END DO

(Apologies for poor pseudo-VB syntax!)

Thanks for your explaination andrewst,the first problem[How to find out there is error object] solved.

The second one unsolved yet because I have > 400 1's to compare !!!!!!

For the looping process , I am too dump to understand it.Can you explain more further ,Dear Andrewst
====================
FOR i = 1 TO 9 DO
isset(10-i) = result AND 2 ** i
END DO
=====================

OK, I'm not sure if I used the correct syntax for VB, but what I was doing was obtaining powers of 2 from 1 to 9, using the syntax 2**i to mean (2 to the power of i) - ** is the power operator in some languages.
So:
2**1 = 2 = 000000010
2**2 = 4 = 000000100
2**3 = 8 = 000001000
etc.

I now see that I missed 2**0 = 1 = 000000001 ! So my code should have been:
FOR i = 0 TO 8 DO
isset(9-i) = result AND 2 ** i
END DO

So what it does is:
1st loop iteration: sets isset(9) = result AND 000000001
2nd loop iteration: sets isset(8) = result AND 000000010
3rd loop iteration: sets isset(7) = result AND 000000100
...
9th loop iteration: sets isset(1) = result AND 100000000

The "isset" array then shows which bits were 1/0 in result: if isset(i) = 0 then the ith bit was 0, else it was 1