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11-19-09, 21:00
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Registered User
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Join Date: Sep 2008
Posts: 11
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Converting DATE to CHAR
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There is date column on the DB2 table (DD/MM/YYYY). I need to create a view so that the date is displayed as a CHAR (format DDMMYYYY).
Tried CHAR_TO and Variable_format functions, but they do not work.
How should I code the select?
Thanks.
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11-19-09, 22:19
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Registered User
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Join Date: Jul 2009
Posts: 150
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easy
Code:
select replace(varchar(col1), '/', '') from your_table
Kara
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11-20-09, 00:47
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Registered User
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Join Date: May 2003
Location: USA
Posts: 5,196
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The DD/MM/YYYY format is dependent on the client you use to access the database. It will not display that way if the client has US territory code, or with a client that uses the ISO format YYYY-MM-DD.
Regardless of the territory code, all dates are stored internally in DB2 as YYYYMMDD in 4 bytes (two numbers per byte since each byte is capable of storing 2 hexidecimal digits 0-F).
__________________
M. A. Feldman
IBM Certified DBA on DB2 for Linux, UNIX, and Windows
IBM Certified DBA on DB2 for z/OS and OS/390
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11-20-09, 03:34
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Registered User
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Join Date: Feb 2008
Location: Japan
Posts: 2,193
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DATE to CHAR (format DDMMYYYY).
Code:
------------------------------ Commands Entered ------------------------------
SELECT date_
, REPLACE(CHAR(date_, EUR), '.', '') AS "DDMMYYYY(replace.char)"
, TRANSLATE('ghefabcd', HEX(date_), 'abcdefgh') AS "DDMMYYYY(translate.hex)"
, SUBSTR(TO_CHAR(date_, 'DDMMYYYY'), 1, 8) AS "DDMMYYYY(to_char)"
FROM (VALUES current_date) q(date_);
------------------------------------------------------------------------------
DATE_ DDMMYYYY(replace.char) DDMMYYYY(translate.hex) DDMMYYYY(to_char)
---------- ---------------------- ----------------------- -----------------
2009-11-20 20112009 20112009 20112009
1 record(s) selected.
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Last edited by tonkuma; 11-20-09 at 03:51.
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11-20-09, 03:57
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Registered User
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Join Date: Feb 2008
Location: Japan
Posts: 2,193
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TO_CHAR() returns VARCHAR(254).
Code:
------------------------------ Commands Entered ------------------------------
DESCRIBE
SELECT date_
, REPLACE(CHAR(date_, EUR), '.', '') AS "DDMMYYYY(replace.char)"
, TRANSLATE('ghefabcd', HEX(date_), 'abcdefgh') AS "DDMMYYYY(translate.hex)"
, SUBSTR(TO_CHAR(date_, 'DDMMYYYY'), 1, 8) AS "DDMMYYYY(substr.to_char)"
, TO_CHAR(date_, 'DDMMYYYY') AS "DDMMYYYY(to_char)"
FROM (VALUES current_date) q(date_);
------------------------------------------------------------------------------
Column Information
Number of columns: 5
SQL type Type length Column name Name length
-------------------- ----------- ------------------------------ -----------
384 DATE 10 DATE_ 5
448 VARCHAR 10 DDMMYYYY(replace.char) 22
448 VARCHAR 8 DDMMYYYY(translate.hex) 23
452 CHARACTER 8 DDMMYYYY(substr.to_char) 24
448 VARCHAR 254 DDMMYYYY(to_char) 17
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