If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below.

 
Go Back  dBforums > Database Server Software > Microsoft SQL Server > sql server

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
  #1 (permalink)  
Old 12-01-11, 03:56
dreamwrox dreamwrox is offline
Registered User
 
Join Date: Dec 2011
Posts: 2
sql server

i want to display the following output where integer value is column data.


{[Advertiser].[AdvertiserKey].&[4000],
[Advertiser].[AdvertiserKey].&[4001],
[Advertiser].[AdvertiserKey].&[4002],
[Advertiser].[AdvertiserKey].&[4003],
[Advertiser].[AdvertiserKey].&[3661],
[Advertiser].[AdvertiserKey].&[3662]
}
Reply With Quote
  #2 (permalink)  
Old 12-01-11, 04:47
PracticalProgram PracticalProgram is offline
Registered User
 
Join Date: Sep 2001
Location: Chicago, Illinois, USA
Posts: 551
Are you asking for permission?
__________________
Ken

Maverick Software Design

(847) 864-3600 x2
Reply With Quote
  #3 (permalink)  
Old 12-01-11, 04:52
dreamwrox dreamwrox is offline
Registered User
 
Join Date: Dec 2011
Posts: 2
No I am asking the function or SP to get this output
Reply With Quote
  #4 (permalink)  
Old 12-01-11, 08:16
r937 r937 is offline
SQL Consultant
 
Join Date: Apr 2002
Location: Toronto, Canada
Posts: 19,525
Quote:
Originally Posted by dreamwrox View Post
No I am asking the function or SP to get this output
where is the output supposed to come from?
__________________
r937.com | rudy.ca
please visit Simply SQL and buy my book
Reply With Quote
  #5 (permalink)  
Old 12-02-11, 12:03
Wim Wim is offline
Registered User
 
Join Date: Nov 2004
Posts: 1,279
Is this what you are looking for?
Code:
DROP TABLE #DaTable
CREATE TABLE #DaTable(
	aNumber	INT	NOT NULL
)

INSERT INTO #DaTAble(aNumber) VALUES
(4000),(4001), (4002), (4003), (3661), (3662) 

DECLARE @T VARCHAR(MAX) ;
SET @T = '' ;

SELECT @T = @T + '[Advertiser].[AdvertiserKey].&[' + CAST(aNumber AS VARCHAR) + '],' + CHAR(09) + CHAR(10)
FROM #DaTable

-- Remove last comma and CR/LF'
SET @T = LEFT(@T, len(@T) - 3)
-- Put the result between '{' and '}'
SET @T = '{'  + @T + '}'

PRINT @T
__________________
With kind regards . . . . . SQL Server 2000/2005/2008/2008 R2 Earned beers: 16
Wim
Beware of bugs in the above code; I have only proved it correct, not tried it. -- Donald Knuth
Grabel's Law: 2 is not equal to 3 -- not even for very large values of 2.
Pat Phelan's Law: 2 very definitely CAN equal 3 -- in at least two programming languages
Reply With Quote
Reply

Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is Off
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On