I have a php script that runs fine on SCO 6.0.0 with Apache 1.3.37 and PHP version 5.2.3, but on SCO 5.0.7 with Apache 1.3.36 and PHP version 4.4.2
I get a file not found message whenever I try to execute the following.




output of /tmp/r5.log

/usr/lib/apache/htdocs/content/en
total 502
-rwxr-xr-x 1 root sys 298 Mar 11 09:41 r5
-rwxr-xr-x 1 root sys 298 Mar 10 16:42 r5.ksh
*************************************************
PHP Script

<?php
session_start();
include_once("../includes/header.php") ;
?>
<!-- CONTENT GOES AFTER THIS POINT -->
<?php
<!-- lines skipped -->
`pwd >/tmp/r5.log`;
`ls -l /usr/lib/apache/htdocs/content/en >>/tmp/r5.log`;

$output=`/u/web/ksh/r5.ksh $UNIQ $uniq $SORTORDER $DIRECTION NAME="$NAME"`;

<!-- $output=`./r5.ksh $UNIQ $uniq $SORTORDER $DIRECTION NAME="$NAME" REF= -->
<!-- $output=`./r5 $UNIQ $uniq $SORTORDER $DIRECTION NAME="$NAME" REF="$REF"`; ->
echo $output;

?>
<!-- ******************************** -->

*******************************
apache error_log - various versions of output=`.......

sh: ./r5.ksh: not found
sh: r5.ksh: not found
sh: /usr/lib/apache/htdocs/content/en/r5.ksh: not found
sh: content/en/r5.ksh: not found
sh: r5.ksh: not found
sh: ./r5: not found
sh: /u/web/ksh/r5.ksh: not found
~

I'm just guessing here:

You give us the file permissions for /usr/lib/apache/htdocs/content/en where it shows k5.ksh but the directory you seem to be trying to run the program in is /u/web/ksh/r5.ksh. Do you have permission to run things here?

As an aside is it wise to have 2 variables called uniq (uniq and UNIQ).

I have tried various versions of this line of code, and none seem to work, I am able to read /u/web/ksh.
The commented lines are other attempts.

The rel 6.0 version has r5.ksh in content/en, and is accessed as ./r5.ksh.

UNIQ and uniq are different, the variables are case sensitive.

Still just guessing:

This doesn't guarantee the apache can read the file though. Can you show us the permissions on the file you want to run /u/web/ksh/r5.ksh? Does the apache user have permission to read that directory and that file? Something like:

Code:

echo `ls /u/web/ksh`;
echo `head /u/web/ksh/r5.ksh`;

If that works then it might be worth seeing if the apache user can run a noddy ksh script just to check the set up of apache.

I guess if it looks confusing to me now then it will look confusing to you in 6 months time

Fixed, after 4 hours.
This line works:

$output=`ksh ./r5.ksh $UNIQ............`;

Thanks,

Jack