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  #1 (permalink)  
Registered User
Join Date: Jul 2009
Posts: 23
while {} echo problems


I have a WHILE loop that works fine, BUT when I add this to it I get an error. I guess my way is NOT how you suppose to do it

My regular while:
$query_3=mysql_query("SELECT * FROM client_order WHERE Client_id = $cid AND order_number = $order_number ");

while ($row_3=mysql_fetch_assoc($query_3)){

echo 'smt....smt';

I need to add:
$paymentRequest->addItem('0001', 'Notebook prata', 2,430.00); // --- 0001 is increasing if I have more than 1 product 0002...000n
The new one:
$query_3=mysql_query("SELECT * FROM client_order WHERE Client_id = $cid AND order_number = $order_number ");

while ($row_3=mysql_fetch_assoc($query_3)){

echo '$paymentRequest->addItem("'.$start_number.'", "'.$productName.'", '.$price.')';

How to I write the code in a correct way that if I have lets say 3 products is will "print" 3 parts like this:
$paymentRequest->addItem('1', 'Notebook prata', 2,430.00);
$paymentRequest->addItem('2', 'Notebook red', 2,430.00);
$paymentRequest->addItem('3', 'Notebook yello', 2,430.00);

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  #2 (permalink)  
Jaded Developer
Join Date: Nov 2004
Location: out on a limb
Posts: 12,297
you need to be carefull dropping in and out of quotes in PHP
although it will accpet a variable inside quotes eg:-
PHP Code:
echo 'A Number is:$ANumericVaraible' 
you cannot do that with an associative array
PHP Code:
echo 'ArrayValue:-",$MyAssocitiveArray['INDEX']; 
however as I read that statement you are trying to add somethign to an array and output something using echo. that isn't going to work as there is no return form the additem method.
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