Unanswered: Can't quite figure this one out... any help?
I have 2 tables, one contains the details for all the documents stored on a server such as the documents name and which directory it is stored in, and the other contains the details for each document version (if there are any) these are paired up using the documents id, per example below
so, as you can see, in the versions table there are 3 versions of 'word.doc' 2 of 'excel.xls' and 1 of 'webpage.html'. i need to write a query that will return all the documents in the versions table who have a matching document in the documents table (that is not the major problem though) the main problem is that i only want to return it if the matching record in the documents table passes certain criteria, this being that it is from a certain site and has a particular type of file name. for example, i would like to return only the document versions whose parent records are '.doc' or '.xls' files, but not html. this would leave me with :
leaving the last record out, as it's parent is a html file.
As a bonus, if you could tell me how to append the parents name to each record so i get a table like this :
Got It! Thanks for your help though. This was the final solution for anyone who's interested
SELECT Docs.Name, DocVersions.TimeCreated, DocVersions.Content
FROM DocVersions INNER JOIN
Docs ON DocVersions.Id = Docs.Id
WHERE (Docs.LeafName LIKE '%.doc' OR
Docs.Name LIKE '%.xls' OR
Docs.Name LIKE '%.ppt' OR
Docs.Name LIKE '%.pdf' OR
Docs.Name LIKE '%.mpp' OR
Docs.Name LIKE ' % .txt ') AND (Docs.DirName LIKE 'sites/archive/%')
I think i confused u all with my talk of leaving out the html document. It wasn't so much i wanted to leave that out as include the others if you know what i mean