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Thread: No of Days in a month

022606, 10:55 #1L O S T in Reality
 Join Date
 Nov 2005
 Location
 San Francisco, CA
 Posts
 506
Unanswered: No of Days in a month
Hi,
I just want to know, is there anything more better solution than this one to find out the no of days in a month ?
I have done this but I am not satisfied,anybody has a smarter solution?
Plz comment..
My Solution :
/* check leap year*/
if year(getdate())%4<>0
set @noofdays=(select case month(getdate())1
when 1 then 31
when 2 then 28
when 3 then 31
when 4 then 30
when 5 then 31
when 6 then 30
when 7 then 31
when 8 then 31
when 9 then 30
when 10 then 31
when 11 then 30
when 12 then 31
end )
else
set @noofdays=(select case month(getdate())1
when 1 then 31
when 2 then 29
when 3 then 31
when 4 then 30
when 5 then 31
when 6 then 30
when 7 then 31
when 8 then 31
when 9 then 30
when 10 then 31
when 11 then 30
when 12 then 31
end)

022606, 12:39 #2World Class Flame Warrior
 Join Date
 Jun 2003
 Location
 Ohio
 Posts
 12,592
Provided Answers: 1Look for mathematical algorithms rather than conditional statements. The resulting code is usually shorter, simpler, and more efficient. I think this will work, though I have not tested it:
Code:declare @DateValue Datetime set @DateValue = getdate() select DatePart(day, DateAdd(day, DateDiff(day, 0, Dateadd(month, 1, @DateValue))1, 0))
http://weblogs.sqlteam.com/brettk/ar...6/02/5528.aspxIf it's not practically useful, then it's practically useless.
blindman
www.chess.com: "sqlblindman"
www.LobsterShot.blogspot.com

022606, 14:00 #3L O S T in Reality
 Join Date
 Nov 2005
 Location
 San Francisco, CA
 Posts
 506
Originally Posted by blindman
declare @datecol datetime,@dat int
set @datecol=getdate()
set @dat=day(DateAdd(day, 1, DateAdd(month, DateDiff(month, 0, @dateCol)+1, 0) ))
print @dat
JoydeepLast edited by rudra; 022606 at 14:31.