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  1. #1
    Join Date
    Mar 2004
    Posts
    10

    Unanswered: Variable scope and debugging

    Hi

    How is a variable's scope handled in bash? Here's the code skeleton.

    var=0
    while read oneLine
    do
    # do some mathematics with $var
    # and the value read from the file

    echo $var # displays variable value correctly for each stage

    done < $inputFile

    echo "Loop done.. $var" # displays accumulated variable value as 0

    When I write set -a var it works, but I'm unable to debug the script any more by specifying set -x. Can we not do both at the same time?

    Thanks in advance.

    - Ram.

  2. #2
    Join Date
    Jan 2004
    Location
    Bordeaux, France
    Posts
    320
    I am using cgywin bash and i don't have this problem :
    Code:
    Var=0
    echo "Before loop Pid:$$ Var:$Var"
    while read oneline
    do
       ((Var += 1))
        echo "   Inside loop Pid:$$ Var:$Var"
    done < a.a
    echo "After loop Pid:$$ Var:$Var"
    the result is :
    Before loop Pid:429381 Var:0
    Inside loop Pid:429381 Var:1
    Inside loop Pid:429381 Var:2
    Inside loop Pid:429381 Var:3
    Inside loop Pid:429381 Var:4
    Inside loop Pid:429381 Var:5
    Inside loop Pid:429381 Var:6
    After loop Pid:429381 Var:6
    Some version of shell creates a subprocess to execute the statements into the loop, in that case the modifications of the environment are lost when exiting the loop.
    Try my script and verify that the Pid is the pid is the same outside and inside the loop.

    You can also try to export your variable.
    Jean-Pierre.

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