I am unable to trace the syntax error reported.... can any one help?
#codefor assert9419
#rchakra18jun2004
function hextodec(hexa) {
result=0;
lon = length(hexa);
#print "long:"lon
for (i = 1; i <= lon ; i++)
{
k = substr(hexa, lon + 1 - i, 1);
#print "k:"k
j=0
if (tolower(k) == "a") j=10;
if (tolower(k) == "b") j=11;
if (tolower(k) == "c") j=12;
if (tolower(k) == "d") j=13;
if (tolower(k) == "e") j=14;
if (tolower(k) == "f") j=15;
if (tolower(k) == 1) j=1;
if (tolower(k) == 2) j=2;
if (tolower(k) == 3) j=3;
if (tolower(k) == 4) j=4;
if (tolower(k) == 5) j=5;
if (tolower(k) == 6) j=6;
if (tolower(k) == 7) j=7;
if (tolower(k) == 8) j=8;
if (tolower(k) == 9) j=9;
#print "j2:"j
result = result + j * 16 ^ ( i -1 );
}
return result;
}
#aeert9419..modified by rajibchak
#dtd:18 june2004
BEGIN{
printf "Cell\tCRC\tCCU\t Unslotted \tSlotted \tOverhead \tCAM\tOrder \tAuthChal \tSSD \tFeatNot \tSDRM \tDBM \tGPM \tECAM \tBSMS\n"}
{
if ( ( $0 ~ /Assert/ ) && ( $0 ~ /9419/ ) ) {
#print l;
split( $0,a );
cell = a[3];
#print cell;
CRC = a[7];
CCU = a[9];
CCU=substr(CCU, 1, 1);
#printf "%s\t%s\t%s\t", cell,CRC,CCU >> salida;
printf "%s\t%s\t%s\r", cell,CRC,CCU;
getline;
getline;
getline;
getline;
getline;
getline;
#print l;
split($0,D);
#print D[3]; print D[4];print hextodec(D[4])
printf "%d\t", hextodec(D[3]);
printf "%d\t", hextodec(D[4]);
printf "%d\t", hextodec(D[5]);
printf "%d\t", hextodec(D[6]);
printf "%d\t", hextodec(D[7]);
printf "%d\t", hextodec(D[8]);
getline ;
split($0,D);
printf "%s\t", hextodec(D[1]);
printf "%s\t", hextodec(D[2]);
printf "%s\t", hextodec(D[3]);
printf "%s\t", hextodec(D[4]);
printf "%s\t", hextodec(D[5]);
printf "%s\t", hextodec(D[6]);
printf "%s\t", hextodec(D[7]);
printf "%s\n", hextodec(D[8]);
}
......
when run thru
awk -f 9419test.awk /omp-data/logs/aplogs/20040617.DBG|more
... throws
awk: syntax error near line 1
awk: bailing out near line 1
pl help....
I tried putting the function statement at the end also... but it says the same at the line containing the function statement...