Hi,

Getting unexpected results from the script line below. I expect to get 3rd parm from each grep'd line into tmp3.out, but I end up getting all 4 parms from each grep'd line (each line contains 4 parms).

ssh $1 "prog1 | grep data | awk '{print $3}';" > tmp3.out

Any ideas on what I am doing wrong here?

Also, tmp3.out is created on host machine. If I want to create tmp3.out on target machine the following doesn't work.

ssh $1 "prog1 | grep data | awk '{print $3}' > tmp3.out ;"

what does the input to awk look like?
have you tried the awk portion of the "pipe" stand-alone?

vlad,

Thanks again for responding, much appreciated.
I don't have a copy of the input here in front of me, but each line has 4 text fields (10 chars or less) separated by spaces.

The weird thing is, if I run the exact same thing from the command-line, it works fine with correct output (3rd field only). I run it in the script and I get the whole line.

From the command line, I do it in 2 steps:
1) ssh <ip-addr>
2) prog1 | grep data | awk '{print $3}' > tmp3.out

Of course, with the command-line version, tmp3.out ends up on the target machine.

hg

Figured this one out, this does the trick:

ssh $1 "prog1 | grep data" | awk '{print $3}'; > tmp3.out