How to differentiate file and folder

freelancers · #1 (**permalink**) 07-28-04, 11:36

;Hi,

hello friends,i would like to write a shell script which it can zip a folder in a certain directory.The problem is inside that directory,it contains some file and folder.I just want to zip the folder but not other file. The script should be able to check the directory,as long as it found a folder it will zip it.So is that any way to do that using shell script?Hope somebody can help me,thanks in advance

SiverSloth · #2 (**permalink**) 07-28-04, 12:00

example code

Code:

for file in ls
do
  if [ -f $file ]
  then 
    gzip $file
  fi
done

There are other variants
-r readable
-w writable
-x executable
and many others - I get mine from
http://www16.boulder.ibm.com/doc_lin....htm#a2659135b
because I work in ksh under AIX

SiverSloth · #3 (**permalink**) 07-28-04, 12:01

Spot the deliberate mistake
it should be

Code:

for file in `ls`
....

Damian Ibbotson · #4 (**permalink**) 07-28-04, 12:36

Or slightly better, use a file expression to derive your file list...

for file in *
do ...

`ls` would be tokenised after the filenames are substituted, so filenames containing spaces would not be assigned to $file as expected.

e.g.

$ touch a "b c"
$ for fname in `ls`; do echo $fname; done
> a
> b
> c

$ for fname in *; do echo $fname; done
> a
> a b

...and the -d flag is probably what you want to test if it is a directory

See: man test

LKBrwn_DBA · #5 (**permalink**) 07-30-04, 14:55

Why not just do:

Code:

find myDir/* -prune -type f -exec gzip {} \;

???

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