How can I split the following and get the index in a list of files?
Eg :
>ls
aaa1.txt
aaa2.txt
aaa3.txt
Now how can put this in a array?. I tried,
lsString=`ls`
But ${lsString[0]} takes whole list as string rather than first string. How can put this list in an array? (suggest if any method without using loop)

thanks

for f in `ls`
do
fileArr[${#fileArr[@]}]=$f
done
echo $fileArr[0]

Any better solution than this?

Try:
or

set -A filearr `ls` WORKS !!!! (the other one doesnt)

thank you very much!

I posted similar recently but its a little hang up of mine, so I'll post again!

DON'T USE 'ls' IF YOU CAN HELP IT! USE A FILE EXPRESSION (i.e. the bit that you provide to 'ls' when you do 'ls /some/where/aFile.*')

Try...

$ mkdir aNewDir
$ cd $_
$ touch a "b c"
$ set -A myArray `ls`
$ echo ${myArray[1]}
b
$ set -A myArray *
$ echo ${myArray[1]}
b c

using ls incorrectly results in the second file "b c" being split into 2 elements, "b" and "c"