extracting the word from the pattern

deebee · #1 (**permalink**) 08-27-04, 16:34

How can i get the whole string or word from a given pattern. for eg.
for a given line :
$ABC_SH/mycode.sh -v aaa -r /mydir/files/data/ ${MYDIR}/hello.sh $DIR/bin
If my search string MYDIR then i should get ${MYDIR}/hello.sh
thanks in advance

vgersh99 · #2 (**permalink**) 08-27-04, 16:51

Code:

echo '$ABC_SH/mycode.sh -v aaa -r /mydir/files/data/ ${MYDIR}/hello.sh $DIR/bin' | sed -e 's/.* \([^ ][^ ]*MYDIR[^ ][^ ]*\).*/\1/g'

deebee · #3 (**permalink**) 08-27-04, 17:13

Awesome!! Thank You!

deebee · #4 (**permalink**) 09-01-04, 16:26

Quote:

Originally Posted by vgersh99

Code:

echo '$ABC_SH/mycode.sh -v aaa -r /mydir/files/data/ ${MYDIR}/hello.sh $DIR/bin' | sed -e 's/.* \([^ ][^ ]*MYDIR[^ ][^ ]*\).*/\1/g'

How can I modify the above to extract if multiple ${MYDIR}/hello.sh exist in the same line
$ABC_SH/mycode.sh -v aaa -r /mydir/files/data/ ${MYDIR}/hello.sh $DIR/bin ${MYDIR}/hi.sh
For eg. (if my pattern is MYDIR )
above should return
${MYDIR}/hello.sh
${MYDIR}/hi.sh

vgersh99 · #5 (**permalink**) 09-02-04, 10:39

nawk -v str='MYDIR' -f deebee.awk myFile.txt

here's 'deebee.awk':

Code:

$0 ~ str {
  for(i=1; i <= NF; i++)
    if ( $i ~ str) 
       print $i
}

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