Hello everyone,

What I want to do is the following:
I have a script that sets the following variable.

TODAY=`date +%m/%d/%Y`
[This will give me 01/18/2005]

I want to know how I can remove the leading zeros from the month and the day? I want to get 1/18/2005 and I want to set it to another variable so that I can pass that date to a script. Does anybody know how I can accomplish this?

Thanks!

date +%m/%e/%Y | sed -e 's/^0//g'

or [with the original "date" format]:

date '+%m/%d/%Y' | sed -e 's#^0##g;s#/0#/#g'

Thanks vlad, so I can just do the following:

TODAY=`date '+%m/%d/%Y' | sed -e 's#^0##g;s#/0#/#g'`
?

that's right.

I know you allready answered this but another way of doing this is to ...

TODAY=`date +%m/%d/%Y'
X=${TODAY#0} # This will assign X to $TODAY minus the beginning characters after the #.

So if today is 01/19/2005 then ${TODAY#0} evaluates to 1/19/2005

For further clarification, if you were to use ${TODAY#01} then it would evaluate to /19/2005 instead of 01/19/2005.

this is ksh/bash specific - I'm not sure if the OP has it.