Shell - Split a line by a phrase?

old_farmer · #1 (**permalink**) 02-08-05, 17:13

vgersh99 · #2 (**permalink**) 02-08-05, 17:26

nawk -f farmer.awk file.txt

farmer.awk:

Code:

BEGIN {
  FS="[|]--EOL--[|]"
  OFS="|--EOL--|"
}
{
   for(i=1; i <= NF; i++)
     if( i < NF )
       print $i OFS
     else
       if (length($i) != 0) print $i OFS
}

old_farmer · #3 (**permalink**) 02-08-05, 19:49

I'm not sure if it works yet.... I'm still trying to concatenate the lines where it looks like what I wrote above. Right now each string before each bar is on separate lines. Once I figure that out, I will run your script to make the new lines only after the --EOL--

vgersh99 · #4 (**permalink**) 02-08-05, 21:30

maybe you should figure out the way to get get where you want to be from where you CURRENTLY are without any intermediate format.

Just an idea..... the rest is up to you!

old_farmer · #5 (**permalink**) 02-09-05, 15:40

Ultimately I want to have this:

"start_here"|ldfjlsdffj|93849340|9034093|"end_here "|
"start_here"|ldfjlsdffj|93849340|9034093|"end_here "|

but right now, all of it is on separate lines but I can't figure out to concatenate only between the "start_here" and "end_here" phrases. So I was trying to concatenate the whole file into one line and then just make a newline after each "end_here" but that's not working either because it creates too big of a line for me to VI. So I'm not sure what to do anymore....

n_i · #6 (**permalink**) 02-09-05, 17:48

Something like this?

Code:

awk 'BEGIN {aline="";} { aline = aline $0 "|" ;} /end_here/ { print aline; aline = ""; }' input.file

This assumes that the first line in the file is "start_here".

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