Hello there. I have a task to make a unix shell script that does the same thing as find command. I should implement only -name -exec -print and -depth parameters.

First step, is there a way to list all the files without using find comand?

Can somebody help me with that?

Tons'a'thanks

man ls

man ls

Yep...
"ls -R"
I figured that out, but wat to do with that list?

Any comments?

Thanks

Do the same thing as find command, depending on the option(s):

For -name, you can use "grep"
For -exec, just execute command replacing the {} with the dir/file name.
For -print, echo the result.
and for -depth, it's going to be a bit more difficult to simulate.

Good luck!

PS: You may want to use: ls -1R

I thought that grep would be the best choise to take out the things from the list, but how do I do that?

e.g.

.:
file1
file2
file3

./dir1:
file1
file2
file3

./dir2/dir3:
file1
file2
file3

if the output is like this, what pattern should I put to grep to take out the files i don't need, but still keep the dir's name, to locate the file?

Millions of thanks...

man grep

To exclude items do: grep -v {pattern}