Hello Friends

I want to search a pattern in a simple file in UNIX. I can use the grep command for this but I want to get the search-pattern line and the next 20 lines redirected in some other file. Is there any option in grep or some other way through which I can get the output.

You can do this with sed or awk. I have always preferred awk to sed, but I think it might be easier to do this one in sed.

should do what you want.



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:-)

bsfbl85:/oq/logs/batch/dl_hist>sed -n -e '/BA7400A/ ,+20p' uoq1002.scriptlog.20060129
Unrecognized command: /BA7400A/ ,+20p
bsfbl85:/oq/logs/batch/dl_hist>sed -n -e '/BA7400A/,+20p' uoq1002.scriptlog.20060129
sed: command garbled: /BA7400A/,+20p


Sorry the command is not working. Am i doing something wrong or there is some alternate way to achieve this.

You must be using a different version of sed than I am. The documentation says that the +n syntax for the second address is a GNU extension. I ran a test of the above command with sed on Fedora Core 3 and it works fine.

I guess the question is what version of UNIX are you running and can you install GNU's version of sed on it. Otherwise I guess you'll need to use awk to do this.



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Can anybody help with awk or some shell script to achieve the task. Friends this is urgent

Place the following code into a file called script.awk:
from the command line run:
awk -f script.awk file-you-want-to-search



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Thanks a lot hyperbole , this worked.