popping element from an array

bhaizone · #1 (**permalink**) 02-24-06, 01:57

How do I pop out an element from anywhere in an array and then the corresponding elements organise themselves accordingly?(working on korn shell)

eg. set -A array 11 12 13 14 15
Now I want to remove 13, then I get
echo ${array[@]} = 11 12 14 15

Bob4480 · #2 (**permalink**) 02-27-06, 19:33

Quote:

Originally Posted by bhaizone

How do I pop out an element from anywhere in an array and then the corresponding elements organise themselves accordingly?(working on korn shell)

eg. set -A array 11 12 13 14 15
Now I want to remove 13, then I get
echo ${array[@]} = 11 12 14 15

Set the element you want to eliminate to null. (Remember Arrays start with 0 (zero))

Code:

 
set -A MY_ARRAY 11 12 13 14 15
echo ${MY_ARRAY[@]}
11 12 13 14 15
 
MY_ARRAY[2]=''
echo ${MY_ARRAY[@]}
11 12 14 15

Bob4480 · #3 (**permalink**) 02-27-06, 19:49

One thing to note. Although it displays properly, the array variable is actually null. There fore you still have 5 elements in the array. If this is a problem you can reset the entire array like this:

Code:

$ set -A MY_ARRAY 11 12 13 14 15
$ echo ${MY_ARRAY[@]}
11 12 13 14 15
$
$  MY_ARRAY[2]=''
$ echo ${MY_ARRAY[@]}  #Array still has 5 elements. Just one is null.
11 12 14 15
$
$ echo ${MY_ARRAY[2]}  #This is now Null.
 
$
$ set -A MY_ARRAY `echo ${MY_ARRAY[@]}`  #Reset Array to 4 elements
$ echo ${MY_ARRAY[2]}  
14
$

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