I am trying to grab output from awk utility in a script and email the output but script is failing. On HP 11 platform, I trying to get the fifth field from "bdf /var" output and send myself an email if /var is 90% or more full but I have not been able to get it right. Here is what I wrote:

#!/bin/sh
bdf /var |awk '{print $5}'|sed s/%// | awk '{if ($1 >= 90) mail "MyId@email.com"}'
exit

And bdf output is like this:
Server> bdf
Filesystem kbytes used avail %used Mounted on
/dev/vg00/lvol7 4194304 1756256 2422400 42% /var

Try this:

Code:

#!/bin/sh
bdf /var |sed 's/%//'|awk '{if ($5 >= 90) print $0;}'|mailx -s"`hostname` -File system full" MyId@email.com

exit

LKB
Your code works but it just sends the output from the first line which happens to be the header info, instead of disk utilization Info. Thanks

Thanks for everyone's input. This is how it was rewritten and resolved:

#!/usr/bin/sh
typeset -i SIZE=$(bdf /var| awk '{getline; sub(/%/,""); print $5;}')
if [[ $SIZE -gt 50 ]]
then
mailx -m -s "[$(date +%m\/%d\/%y)] $rescon /var at 50+%!"MyId@email.com
fi
exit 0