Dear All,

Good day. I'm having problems with my KSH.

I have a text file with lines like this: (impsrc.lst)

!WK29_20070720_1109_v26

=SCMUIUSER

This is my script:

cat impsrc.lst | while read line
do
{if line contains '=' then do} <--- don't know how to do this
filez=${line##*"="}
echo "Found: "$filez
{end if}
done
exit 1


What it does is strip away the charater '=' and just prints the lines without the '='. But it also prints all the lines which start with '!'. All I want is to just print the lines starting with '=' without the '='.

I was thinking of:

1. check if line contains '='
2. if yes then print without '='

So the output should be:
SCMUIUSER

Right now I get this as output:
!WK29_20070720_1109_v26

SCMUIUSER

Thanks in advance for all the help.

You can do something like that :

Thanks a lot aigles. It worked after a few changes. :-)

If all you want is to print the lines containing =
And strip the = and everything in front of the =

sed -n 's/\(.*\)=/Found: /p' impsrc.lst

or even ...
Which just shows lines that start with = and then strips the = at the start of the line.

Mike

With zsh:

In the example from aigles, would you put words you are looking for in quotes? I need to parse a file looking for specific words in the lines.

Thank you.

I should clarify that I need to see what is in the file line by line, so I cannot use grep.