find and replace a string

saccskiz · #1 (**permalink**) 09-12-07, 19:21

I currently have a shell script (findreplace.ksh) that finds a word and replaces it with another word for all files in the specified directory
#findreplace.ksh :
perl -e "s/${1}/${2}/g;" -pi $(find ${3}/ksh -type f)

Hence I would run the script as :
findreplace dummy nodummy temp

This would replace all occurances of dummy to nodummy in the temp/ksh folder.

Now how do I do the following :
If my arguments ${1} and ${2} have spaces in them, what option can I give to make it work ?
For example, I need to replace the word <I am a Dummy> with <Not anymore a dummy" in the same fashion ?
Also, I am interested in knowing if there are any other options to doing a find and replace(besides the perl command)
Thanks

vgersh99 · #2 (**permalink**) 09-12-07, 19:36

Code:

findreplace 'I am a Dummy' 'Not anymore a dummy' temp

Tyveleyn · #3 (**permalink**) 09-15-07, 05:12

Type on the command line:

Code:

$ for i in "`ls *"I am a dummy"*`"
> do                                
> mv "$i" "`echo "$i" | sed 's/I am a dummy/Not anymore a dummy/'`"                               
> done

This is done in Linux so maybe the quoting thing works a little different in other UNIX systems. Spaces in filenames is not what UNIX is made for anyway...

Regards

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