I have the follow command

ls -l | grep 'Feb 21' | awk '{print "awk /SESSIONID:/ {print $0} "$9 ">> join.file" }'> a.a

The commando run sucessfully

But i need put single quota in print

Like that

ls -l | grep 'Feb 21' | awk '{print "awk '/SESSIONID:/ {print $0}' "$9 ">> join.file" }'> a2.a

and begin '/SESSIONID
and the end $0}'

But if i try run this command.. i have an error

oracle [Amadeus1]% ls -l | grep 'Feb 21' | awk '{print "awk '/SESSIONID:/ {print $0}' "$9 ">> join.file" }'> a2.a
awk: Cannot find or open file {print.

The source line number is 1.
oracle [Amadeus1]%


how i can put this single quota in awk print command

Thanks

did your other question this morning get answered fully?

Escape the single quote inside the AWK script:

I apply your recomendation but, dont work

When i executed, dont do it anything.


% ls -l | awk '{print "awk \'/SESSIONID:/ {print $0}\' "$9 ">> join.file" }'> a.a
>
>
>ctrol +C
%

Then you can use the hex code point for the character (assuming you use ASCII/UTF-8):

I try but dont work

oracle [Amadeus1]% ls -l | awk '{print "awk \x27/SESSIONID:/ {print $0}\x27 "$9 ">> join.file" }'> a.a
awk x27/SESSIONID:/ {print $0}x27 ora_1000038.aud>> join.file
awk x27/SESSIONID:/ {print $0}x27 ora_1000691.aud>> join.file
awk x27/SESSIONID:/ {print $0}x27 ora_1000736.aud>> join.file
awk x27/SESSIONID:/ {print $0}x27 ora_1000808.aud>> join.file
awk x27/SESSIONID:/ {print $0}x27 ora_1000935.aud>> join.file

put x27 when must be put '

Any other idea.

Regards.

It works fine for me:

My S.O is Tru 64 unix.

Regards,

Then check if you have GNU awk installed - maybe it is named "gawk"?