shell script for pattern matching

deebee · #1 (**permalink**) 10-06-09, 15:54

I am looking for a case statement pattern matching on a unix comment line.

For eg. given input in a file,
#aa=1
b=2
c=3
#ddd=4

so, the comment lines needs to be skipped while reading.

case "$line" in
aa) do_something;;
b) do_something;;
c) do_something;;
ddd) do_something;;
#) ;; /*NOT WORKING!! */
*) invalid input;;
esac

I tried couple of patterns but not working.

Thanks.

mike_bike_kite · #2 (**permalink**) 10-06-09, 16:16

It might help if you give an idea what the "do something" is.
Do the # lines get ignored?
Does the "aa" have to be at the start?
Does it matter what order you do the "somethings" in?

deebee · #3 (**permalink**) 10-06-09, 17:04

Quote:

Originally Posted by mike_bike_kite

It might help if you give an idea what the "do something" is.
Do the # lines get ignored?
Does the "aa" have to be at the start?
Does it matter what order you do the "somethings" in?

All I want is comment lines (starts with #) need to be ignored. There is no certain order. Thanks.

LKBrwn_DBA · #4 (**permalink**) 10-06-09, 17:09

maybe something like this:

Code:

while read line
do
  case "$line" in
    aa*) do_something;;
     b*) do_something;;
     c*) do_something;;
   ddd*) do_something;;
    \#*) echo "this is a remark";;
      *) echo "invalid input";;
  esac
done

deebee · #5 (**permalink**) 10-06-09, 17:22

Quote:

Originally Posted by LKBrwn_DBA

maybe something like this:

Code:

while read line
do
  case "$line" in
    aa*) do_something;;
     b*) do_something;;
     c*) do_something;;
   ddd*) do_something;;
    \#*) echo "this is a remark";;
      *) echo "invalid input";;
  esac
done

\#*) echo "this is a remark";;
WORKED! Thank you very much.

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