Help in replace method

SeenuGuddu · #1 (**permalink**) 11-16-09, 11:38

Hi Gurus,

VARIABLE=john_*_has_*_s

i want to replace the * with digits 09100 and 0010101

to print the echo john_09100_has_0010101_s

Thanks

mike_bike_kite · #2 (**permalink**) 11-16-09, 11:49

is this homework?

SeenuGuddu · #3 (**permalink**) 11-16-09, 12:02

no Mike i did .. but i am getting this

echo john_*_has_*_s | sed 's/*/10101/'

john_10101_has_*_s

fine but the second * to replace with another id..?

mike_bike_kite · #4 (**permalink**) 11-16-09, 12:05

Why not pipe the output through another sed command similar to your first one?

SeenuGuddu · #5 (**permalink**) 11-16-09, 23:54

Thanks Mike .. Got it

SeenuGuddu · #6 (**permalink**) 11-17-09, 10:30

Hi Mike
echo john_*_has_*_s | sed 's/*/10101/' | sed 's/*/789/'

if it is dynamically..?

echo john_${var1}_has_${var2}_s

mike_bike_kite · #7 (**permalink**) 11-17-09, 11:04

Quote:

Originally Posted by SeenuGuddu

Hi Mike
echo john_*_has_*_s | sed 's/*/10101/' | sed 's/*/789/'

if it is dynamically..?

echo john_${var1}_has_${var2}_s

I appreciate it has a question mark but normally questions start with words like how, what and why. I'm not at all sure what you're trying to do or why you're doing it in the first place. Would it be better to try and explain why you want to do this?

SeenuGuddu · #8 (**permalink**) 11-20-09, 01:48

Hi Mike this is working finee with tested values

#!/bin/ksh

V_DATE="2007-11-30"
V_ID=789
V_NAME="john_${V_ID}_has_${V_DATE}_s"

FILE_NAME=`echo ${V_NAME}`

echo ${FILE_NAME}

Buttt the problem is

the first two values will come dynamically

and the file will looks like "john_${V_ID}_has_${V_DATE}_s*" soo i have to get the file from remote system and i have to further processs based on the
date and ID

"filename" i am storing it in varaible and ID and Date aswell

But when i `echo ${FILE_NAME}` it prints

john_${V_ID}_has_${V_DATE}_s*

its nt replacing the values

can u give the solution for this...

mike_bike_kite · #9 (**permalink**) 11-20-09, 04:13

I couldn't see any major issues in your code so I entered it into my system :

Code:

#!/bin/ksh

V_DATE="2007-11-30"
V_ID=789
V_NAME="john_${V_ID}_has_${V_DATE}_s"
FILE_NAME=`echo ${V_NAME}`

echo "V_DATE=$V_DATE"
echo "V_D=$V_ID"
echo "V_NAME=$V_NAME"
echo "FILE_NAME=$FILE_NAME"

exit

And ran it which produced the following which looked correct :

Code:

V_DATE=2007-11-30
V_D=789
V_NAME=john_789_has_2007-11-30_s
FILE_NAME=john_789_has_2007-11-30_s

Can you check you're using double quotes everywhere - single quotes won't translate the variable values ie make sure you type " and not ' or '' (which is actually two single quotes typed one after the other).

Another point is that it would be easier to read if you had FILE_NAME=$V_NAME rather than printing out V_NAME and capturing the output. Even better might be to just use one variable rather than two holding the same value.

Also where did the * come from in FILE_NAME - I can't see how that could of been set using your code.

Mike

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