Formatting the words in a file

regtha · #1 (**permalink**) 01-25-10, 18:24

I have a file named test which has content like below

abc
123
456
jshd
uieh
sjdfsdf
sjdfhjkah
jeff
jenny

I want the result as

'abc','123','456','jshd','uieh','sjdfsdf','sjdfhjk ah','jeff','jenny'

after formatting the above string

I have one logfile which has thousands of rows. From this file I have to select the lines which does not has any of the string from the file 'test'

please let me know how to do

mike_bike_kite · #2 (**permalink**) 01-25-10, 19:19

Traditionally homework is set for students to allow them to practice what they've learnt, not for students to hand it out to others to do.

kitaman · #3 (**permalink**) 01-25-10, 19:24

Code:

#!/bin/ksh
LIST=; export LIST
separator=" "
while read token
do
        LIST=$LIST$separator$token
        separator=" |"
done <testfile
grep -E -v "$LIST" logfile >/exceptionlist

Damn, I see a mistake in it.

LKBrwn_DBA · #4 (**permalink**) 01-26-10, 09:59

Quote:

Originally Posted by regtha

please let me know how to do

man grep

SYNTAX
grep <options> [-f file] [file...]

OPTIONS
`-f FILE'
Obtain patterns from FILE, one per line. The empty file contains
zero patterns, and therefore matches nothing.

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