get file name.file size,record count using shell script

qutesanju · #1 (**permalink**) 09-20-11, 23:43

I need to get file name file size rcord count from the specified directory e.g OUTFILES/archive

at present i tried like this ...
test.sh
v_Dir=$1
echo "the directory to cd to is "$1

if [ $# -ne 1 ]
then "echo you must pass in the directory"

else
cd $v_Dir
for x in `ls -lt |grep -v ^d|awk '{print $9}'`
do

x=`ls -l $0 | awk '{print $9 "|" $5}'`
y=`awk 'END {print NR}' $0`
echo $x '|' $y
done
fi

and its execution would be
test.sh OUTFILES/archive > testb.log 2>&1

kitaman · #2 (**permalink**) 09-21-11, 09:06

The grep statement should be

Code:

grep -v "^d"

When I ran your code, I had problems with the awk statements because the directory was changed.
So...simplified.

Code:

ls -l $1|grep -v "^d"|while read a b c d size f g h name
do                                                      
   echo $name $size                                        
done

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