Bourne Shell help

mintos123 · #1 (**permalink**) 10-05-11, 04:45

i am trying to write a script which it echos its script file name and the value of its odd arguments.
i got the echo filename part..but im not sure how to echo its odd arguements.
for example
the output of script Good_script is a very good script
should be
Good_script
is
very
script

i have came up with code

Code:

#!/bin/sh
filename=`basename $0`;
echo $filename;
i=1
	until [ $i -gt $# ]
	do
 	y=`echo "$i % 2" | bc`
 		if [ $y -eq 1 ]; then
		echo $i
		fi
	i=`echo "$i + 1" | bc`
	done

but right now, it only echos the filename and the numerical value
say if it was Good_script a b c d e
it would output
Good_script
1
3
5
any help?

kitaman · #2 (**permalink**) 10-05-11, 08:13

Code:

#!/bin/sh                            
filename=`basename $0`;              
echo $filename;                      
last=$#                              
i=1                                  
        until [ $i -gt $last ]       
        do                           
        y=`echo "$i % 2" | bc`       
                if [ $y -eq 1 ]; then
                echo $i $1           
                fi                   
        shift                
        i=`echo "$i + 1" | bc`       
        done

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