reading file in unix

pp8771 · #1 (**permalink**) 12-20-12, 17:40

In a file (testfile.lst) I have the contents as:

Wf : S1 : D1
#Wf2 : S2 : d2
Wf3 : S3 : D3
Wf4 : S4 : d4

using looping in unix i want to read the contents where it does not begin with hash.

I want to obtain the output as

Wf is S1 and D1;
Wf3 is S3 and D3;
Wf4 is S4 and d4;

provide me with a shell scipt to do this

Kind Regards
P

Pat Phelan · #2 (**permalink**) 12-20-12, 19:19

Code:

awk "!/^#/{print}"

-PatP

spacebar · #3 (**permalink**) 12-20-12, 23:48

Below is one way to do it in shell script:

Code:

# Script:  test.sh
while IFS=":" read field1 field2 field3
do
  if [ "${field1:0:1}" == "#" ]; then
    continue
  fi
  echo $field1 $field2 $field3
done <t


$ cat t
Wf : S1 : D1
#Wf2 : S2 : d2
Wf3 : S3 : D3
Wf4 : S4 : d4


$ test.sh
Wf S1 D1
Wf3 S3 D3
Wf4 S4 d4

pp8771 · #4 (**permalink**) 12-21-12, 04:02

Thanks..But another requirement come up.
In a file (testfile.lst) I have the contents as:

Wf : S1 : D1 : U
#Wf2 : S2 : d2 : V
Wf3 : S3 : D3 : W
#Wf6 : S6 : D6 : W

Wf4 : S4 : d4 : X

using looping in unix i want to read the contents where it does not begin with hash.

I will pass an argument W(fourth field) with the shell script and I want to obtain the output as:

Wf3 is S3 and D3
Wf4 is S4 and d4

When it first encountered W in the fourth column then that line and all succeeding lines in the file will comprise the output.

provide me with a shell scipt to do this

Kind Regards
P

kitaman · #5 (**permalink**) 12-21-12, 09:04

Code:

# Script:  test.sh
firstW=0
while IFS=":" read field1 field2 field3 field4
do
  if [ "${field1:0:1}" == "#" ]; then
    continue
  fi
   if [ "$field4" =  "  W" ]
      then
      firstW=1
    fi
   if [ $firstW -eq 1 ]
  then
  echo $field1 is $field2 and $field3 
  fi
done <t

You will have to test whether field4 has a leading space since IFS is set to colon.

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