example:
under a directory name mydir, I have the following files....

/mydir $ ls -al
total 9
drwxrwxr-x 3 db2adm00 grpdba 512 Nov 18 14:14 .
drwxr-xr-x 19 db2adm00 grpdba 3584 Nov 18 14:12 ..
-rw-rw-r-- 1 db2adm00 grpdba 0 Nov 18 14:14 .myhiddenfile
-rw-rw-r-- 1 db2adm00 grpdba 0 Nov 18 14:13 mybackup.tgz
-rw-rw-r-- 1 db2adm00 grpdba 0 Nov 18 14:12 myfile.txt
lrwxrwxrwx 1 db2adm00 grpdba 10 Nov 18 14:13 mylink -> myfile.txt
drwxrwxr-x 2 db2adm00 grpdba 512 Nov 18 14:12 mysubdir


1. how can I list the normal file like the following?
mybackup.tgz
myfile.txt

2. how can I list the normal file and the hidden file like the following?
.myhiddenfile
mybackup.tgz
myfile.txt

3. how can I just exclude the directory name?
.myhiddenfile
mybackup.tgz
myfile.txt
mylink


anyone please help, thanks for advance :-)

There may be options in ls for what you want, but I don't know any of them ...

I do in the following way :

1) Have to give a thought

2) ls -al | grep ^- | nawk '{print $NF}'

3) ls -la | grep -c ^d | nawk '{print $NF}'


HTH

Sathyaram

You could also take a look at the 'test' command (man test).

e.g.

for file in *
do
test -f $file && echo $file
done

Not sure I understand what you're asking for exactly, but here goes:

1. ls
2. ls -a
3. ls -aF|grep -v /
(not sure exact ls option but this will work)