Hi

I am writing a script that uses the df command which uses an awk script to do formatting this is the output of the df command..

/ (/dev/root ): 662794 blocks 213507 i-nodes
/stand (/dev/boot ): 11868 blocks 4992 i-nodes
/u (/dev/u ): 1320257 blocks 762824 i-nodes

and this is my awk script which will format this input..

BEGIN { FS = "\n" } { RS = "[ \t]+" }
{ print $1 }

when i feed input from df -k to this awk script it prints the first two lines rather than only first line as i specify $1

# df -k | awk -f ft.awk
/ (/dev/root ): 662793 blocks 213506 i-nodes
/stand (/dev/boot ): 11868 blocks 4992 i-nodes


i only need it to print first line any ideas thanks...

xor

try this
# df -k | grep "root" | awk -f ft.awk

To set the field seperator to a newline, use FS="". That said, if you want to use awk just to print a particular line, do it like this...

df -k | awk 'NR==1{print; exit}'

The use of 'exit' isn't really necessary but for larger files, you proabably wouldn't want to continue reading in lines.

You could also use 'head' in this instance...

df -k | head -1


Damian