How to pass arguments to a function?

preetikate · #1 (**permalink**) 02-10-04, 02:33

Hi,
I have two shell variables $t1 and $t2 which I need to pass to a function in a shell script. The function will do some computation with those two variables and echo the resultant. But I do not know how to pass teh arguments.
The function written is
f1()
{......
........
}

What should be the syntax to pass arguments $t1 and $t2 to this function.
Help would be appreciated!

reneeb · #2 (**permalink**) 02-10-04, 03:13

may be this example will help you:

Code:

#!/bin/bash

function count_from_to()
{
  i=$1			# i gets value of param1
  while [ $i -le $2 ]	# while param2 greater than i
  do
    echo $i		# print i
    let i=$i+1		# increment i
  done
}

# main program

read -p "from: " number1	# reading starting number
read -p "to: " number2		# reading final number
count_from_to $number1 $number2	# call function passing the two values

preetikate · #3 (**permalink**) 02-10-04, 03:30

Thanks a lot!
Its done now!

Internet Services

Web Development

Digital Marketing

Consumer Tech