Cut the Last Field

murali_vijayan · #1 (**permalink**) 02-25-04, 03:47

How to Cut the Last Field in an output i received.

Ex : $ ls -lt ./module/src/prog-name.pc
./module/src/prog-name.pc

I need to display only the last field only ie. prog-name.pc

how to do that.

aigles · #2 (**permalink**) 02-25-04, 04:22

If you want to display the last field only :

Code:

ls -lt ./module/src/ | awk '{print $NF}'

To display the file name only from a full path :

Code:

basename ./module/src/prog-name.pc

You can combine the two :

Code:

basename `ls -lt ./module/src/ | awk '{print $NF}'`

arik.fish · #3 (**permalink**) 02-29-04, 18:31

Isn't it simpler :

for file in `ls -lt ./module/src/`
do
basename $file
done
or in one line :
for file in `ls -lt ./module/src/`;do basename $file ; done

aigles · #4 (**permalink**) 03-01-04, 03:36

That doesn't work for the result of a 'ls -lt' command, because the result contains not only the filename but also perms, owner, group, date.

For a 'ls -t' command, it's ok.

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