I want to use the find command in a shell script to create list all image files in a directory, the current line in my code is:

find $TEMP_DIR/ -name "*.tif" > $LOAD_FILE

which produces a file like:

/dir1/dir2/dir3/test1.tif
/dir1/dir2/dir3/test2.tif
/dir1/dir2/dir3/test3.tif

How can I remove the directory path so the file only contains a list of tif files.

Any help would be appreciated as you can probably tell I am no UNIX expert.

Cheers.

sed 's!.*/!!' => replace (s) all chars until last / (.*/) by nothing ()

Thanks that worked a treat!

You could also do this using find's 'exec' option...

find "$TEMP_DIR" -name "*.tif" -exec basename {} \;

Damian