Problem Unix (i am not expert on use of Unix)

sistemi · #1 (**permalink**) 04-06-04, 06:32

How I can obtain a list of files having same year?
For example :all files of directory /tmp/pippo/ having creation year 2003?

ika · #2 (**permalink**) 04-06-04, 07:40

Quote:

Originally posted by sistemi
How I can obtain a list of files having same year?
For example :all files of directory /tmp/pippo/ having creation year 2003?

ls -la /tmp/pippo | grep 2003 - simplest way
If you would like grep by date column only you need to use "awk"

aigles · #3 (**permalink**) 04-06-04, 08:28

Quote:

Originally posted by ika
ls -la /tmp/pippo | grep 2003 - simplest way
If you would like grep by date column only you need to use "awk"

There are two problems with this solution :
1) A filename may contains the year
2) For files newer than 6 months, ls don't display the year

The following script use find to select the files.

Code:

year=${1:-`date +%Y`}

syear=`expr $year - 1`
since_date=${syear}12312359.59
since_file=/tmp/since_${year}.$$

byear=`expr $year + 1`
before_date=${byear}01010000.00
before_file=/tmp/before_${year}.$$

touch -t $since_date $since_file 
touch -t $before_date $before_file 

find . ! -name . -prune ! -newer $before_file -newer $since_file | xargs ls -lad

rm -f $since_file $before_file

Run this script with the requested year as argument (default is current year).
If you want to include files in sub-directories, remove '! -name . -prune' from the options of the find command.

sistemi · #4 (**permalink**) 04-06-04, 10:02

thanks you very much!!
There are two problems with this solution :
1) A filename may contains the year
2) For files newer than 6 months, ls don't display the year

The following script use find to select the files.

Code:

year=${1:-`date +%Y`}

syear=`expr $year - 1`
since_date=${syear}12312359.59
since_file=/tmp/since_${year}.$$

byear=`expr $year + 1`
before_date=${byear}01010000.00
before_file=/tmp/before_${year}.$$

touch -t $since_date $since_file 
touch -t $before_date $before_file 

find . ! -name . -prune ! -newer $before_file -newer $since_file | xargs ls -lad

rm -f $since_file $before_file

Run this script with the requested year as argument (default is current year).
If you want to include files in sub-directories, remove '! -name . -prune' from the options of the find command. [/SIZE][/QUOTE]

ika · #5 (**permalink**) 04-06-04, 11:28

Quote:

Originally posted by aigles
There are two problems with this solution :
1) A filename may contains the year
2) For files newer than 6 months, ls don't display the year

The following script use find to select the files.

Code:

year=${1:-`date +%Y`}

syear=`expr $year - 1`
since_date=${syear}12312359.59
since_file=/tmp/since_${year}.$$

byear=`expr $year + 1`
before_date=${byear}01010000.00
before_file=/tmp/before_${year}.$$

touch -t $since_date $since_file 
touch -t $before_date $before_file 

find . ! -name . -prune ! -newer $before_file -newer $since_file | xargs ls -lad

rm -f $since_file $before_file

Run this script with the requested year as argument (default is current year).
If you want to include files in sub-directories, remove '! -name . -prune' from the options of the find command.

As I said that is the simples (primitive) solution with many disadvantages but very quick...

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